Hi

find the standard form of the equation by completing the square

196x^2+9y^2+392x+54y-1487=0

 196(x+1)^2 -196 + 9(y+3)^2 -81 - 1487 = 0

  196(x+1)^2  + 9(y+3)^2 = 1764

  (x+1)^2/9  + 9(y+3)^2/196 = 1

 

Elipse: a = 3 and b = 14  C(-1,-3)



 

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