SOLUTION: What is the standard form of 9x^2- 16y^2 -18x + 96y - 279=0

Algebra.Com
Question 426088: What is the standard form of 9x^2- 16y^2 -18x + 96y - 279=0
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!

Hi
standard form of
9x^2- 16y^2 - 18x + 96y - 279=0 |Note use of ^ (uppercase 6)
9[(x-1)^2 -1] -16(y-3)^2]-9] - 279 = 0
9(x-1)^2 - 9 -16(y-3)^2 + 144 - 279 = 0
9(x-1)^2-16(y-3)^2 = 144

RELATED QUESTIONS

what is the domain of... (answered by Fombitz)
What is the equation of the ellipse in standard form?... (answered by lwsshak3)
I was wondering if anyone could help me determine what type of figure is given, then... (answered by venugopalramana)
What is the standard form of... (answered by lwsshak3)
How do I solve and graph the equation... (answered by Edwin McCravy)
25x^2+16y^2-50x-96y-231 (answered by Fombitz)
16y^2-9x^2+18x+64y-89=0 (answered by Edwin McCravy)
find the standard form:... (answered by jsmallt9)
9x^2-16y^2+36x+64y=172 What type of conic? Standard Form? (answered by stanbon)