# SOLUTION: Choose the equation that best represents an ellipse for the given foci and co-vertices. foci (+or- 2, 0) co-vertices (0, +or- 4) (a) x^2/20 + y^2/16 =1 (b) x^2/16 + y^2/20

Algebra ->  Algebra  -> Quadratic-relations-and-conic-sections -> SOLUTION: Choose the equation that best represents an ellipse for the given foci and co-vertices. foci (+or- 2, 0) co-vertices (0, +or- 4) (a) x^2/20 + y^2/16 =1 (b) x^2/16 + y^2/20       Log On

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 Question 421565: Choose the equation that best represents an ellipse for the given foci and co-vertices. foci (+or- 2, 0) co-vertices (0, +or- 4) (a) x^2/20 + y^2/16 =1 (b) x^2/16 + y^2/20 =1 (c) x^2/9 - y^2/36= 1 (d) y^2/6 - x^2/1 =1Answer by Edwin McCravy(8909)   (Show Source): You can put this solution on YOUR website!Choose the equation that best represents an ellipse for the given foci and co-vertices. ``` foci (+or- 2, 0) co-vertices (0, +or- 4) (a) x^2/20 + y^2/16 =1 (b) x^2/16 + y^2/20 =1 (c) x^2/9 - y^2/36= 1 (d) y^2/6 - x^2/1 =1 All the choices have center (0,0) It can't be (c) or (d) for the minus sign tells us they're hyperbolas, not ellipses. It can't be (b) because the smaller denominator being under the x² term means the ellipse has vertices and foci on the y-axis and covertices on the x-axis, and is shaped like this "" . But the given foci are on the x-axis and the covertices are on the y-axis, making it shaped like this "". So by elimination, the answer is (a). Edwin```