SOLUTION: How do you find the equation of the hyperbola with the following information: Foci (-4,0) (4,0) and asymptote is y=-x

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Question 418797: How do you find the equation of the hyperbola with the following information: Foci (-4,0) (4,0) and asymptote is y=-x
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

Standard Form of an Equation of an Hyperbola opening right/left is  

%28x-h%29%5E2%2Fa%5E2+-+%28y-k%29%5E2%2Fb%5E2+=+1 where Pt(h,k) is a center  with vertices 'a' units right and left of center. 

  Asymptote is y  = -x   b/a = 1 or a = b  

Foci at (-4,0) and (4,0) Pt(0,0) is the center 

4 = sqrt(a^2 + a^2) = sqrt(2a^2)  a = sqrt(8)= b

   x^2/8 - y^2/8 = 1