SOLUTION: Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function f(x)=2x^2-12x+20

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Question 410585: Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function
f(x)=2x^2-12x+20

Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!

Hi
Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function
f(x)=2x^2-12x+20
Using the vertex form of a parabola, where(h,k) is the vertex
f(x)=2(x^2-6x)+20 |completing square to put into vertex form
f(x)=2[(x-3)^2 - 9] +20
f(x) = 2(x-3)^2 -18 + 20
f(x) = 2(x-3)^2 + 2 |Vertex is Pt(3,2) Line of symmetry is x= 3


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