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graph the equation equal to: 2x^2-2x-2y-1=0 and find the vertex, focus point and axis of symmetry.
Standard form for parabola: (x-h)^2=4p(y-k),(h,k) being the (x,y) coordinates of the vertex,p=distance from vertex to focus or vertex to directrix(in the opposite direction) on the axis of symmetry.
Completing the sqare:
equation in standard form:
axis of symmetry = x=1/2
Directrix = y=-1