SOLUTION: using the formulas for parabolas, graph and write the equations of parabolas with the following properties. Graph an extra point other than a vertex. The Parabola with focus (0, 5)

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Question 40448: using the formulas for parabolas, graph and write the equations of parabolas with the following properties. Graph an extra point other than a vertex. The Parabola with focus (0, 5) and directrix y= -5.
Found 2 solutions by Nate, stanbon:
Answer by Nate(3500)   (Show Source): You can put this solution on YOUR website!
From the information we can tell that the vertex is at the origin.
P = 1/(4a) when is the distance from the vertex to the focus and from the vertex to the directrix
5 = 1/(4a)
20a = 1
a = (1/20)
Use:


For another point, pick ....


Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=0 is zero! That means that there is only one solution: .
Expression can be factored:

Again, the answer is: 0, 0. Here's your graph:

Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
using the formulas for parabolas, graph and write the equations of parabolas with the following properties. Graph an extra point other than a vertex. The Parabola with focus (0, 5) and directrix y= -5.
Draw the picture. Do you see that the parabola must be opening upward.
Therefore the general form is x^2=4py
P is half the distance from the directrix to the focus or p=5
EQUATION:
x^2=4(5)y
y=(1/20)x^2
An extra point would be (1,1/20)
Cheers,
Stan H.

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