SOLUTION: Graph the parabola
x^2+8x-5y+21=0
I need help with the points. Thanks
Algebra.Com
Question 404479: Graph the parabola
x^2+8x-5y+21=0
I need help with the points. Thanks
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
x^2+8x-5y+21=0
----
5y = x^2+8x+21
---
y = (1/5)(x^2+8x+21)
----
If x=0, y = 21/5
If x=-6,y = 9/5
If x=-4,y = 1
If x=-2,y = 9/5
If x= 0, y = 21/5
--------------
=================
Cheers,
Stan H.
RELATED QUESTIONS
I have to graph: 8x-7y-14=0
I need the y=mx+b formula of the 4 plot points to graph... (answered by checkley71)
Can someone please help me with this problem? I can't get it.
Given f(x) = x^2 – 8x - 20 (answered by Earlsdon,venugopalramana)
I need the following please:
standard form for: x^2-4x-2y-8=0
vertex and focus of... (answered by stanbon)
Hi need some help with this one:
Find the vertex, graph and find the x-intercepts of... (answered by Gogonati)
Question:
Find the equation for the parabola with focus at (-1,-1) and vertex at (4,-1)
(answered by sdmmadam@yahoo.com)
ah help meeeeeee :[[ it says determine whether each parabola opens upward,downward,left... (answered by stanbon)
i need help with the following questions PLEASE!!!!
Solve using the multiplication... (answered by solver91311)
How would I graph the circle
x^2+... (answered by stanbon,MathLover1)
please help me plot the graph of the equations
4x-6y=12and x-5y=10... (answered by stanbon)