SOLUTION: graph the equation. identify the focus and directrix of the parabola, y^2=-4x

Question 400901: graph the equation. identify the focus and directrix of the parabola, y^2=-4x
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
graph the equation. identify the focus and directrix of the parabola, y^2=-4x
..
y^2=-4x is of the form, y^2=-4px
This is a parabola with horizontal axis of symmetry,y=0, opening leftward.
vertex (0,0)
4p=4
p=1
..
The focus is on the line of symmetry so its y-coordinate=0
Its x-coordinate is "p" or 1 unit to the left of the vertex.
Therefore, the (x,y) coordinates of the focus is (-1,0)
..
The directrix is a vertical line "p" or 1 unit on the right side of the vertex, that is, x=1
..
ans: The focus is at (-1,0), and equation of the directrix is x=1
see the following graph

RELATED QUESTIONS
how do you identify the vertex, focus, and directrix of the parabola y=x^2+4x+3 And... (answered by stanbon)

identify the focus and directrix of the parabola given by {{{ y^2 = -4x... (answered by lwsshak3)

Graph the equation. Identify the focus and directrix of the parabola. y^2=24x Thank (answered by t_hc_04)

Identify the vertex, focus, and Directrix of the graph of this parabola: (x-1)^2 =... (answered by ewatrrr)

Identify the focus, directrix, and axis of symmetry then graph the parabola... (answered by lwsshak3)

Identify the vertex, focus, and directrix of the parabola.... (answered by stanbon)

draw the graph of the parabola y*y+4x=0 also findn it's focus and directrix? (answered by josgarithmetic)

Find the vertex, focus and directrix of the parabola and sketch the graph... (answered by josgarithmetic)

How do you find the focus and directrix of the parabola y=x^2-4x+4 and graph it? (answered by MathLover1)