SOLUTION: What is the equation of a circle with a diameter having endpoints at (3,2) and (9,10)?

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Question 395303: What is the equation of a circle with a diameter having endpoints at (3,2) and (9,10)?
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

 D = sqrt+%28%28x1-x2%29%5E2%2B%28y1-y2%29%5E2%29%29

(9,10) and 

(3,2)   Diameter = sqrt+%28%286%29%5E2%2B%288%29%5E2%29%29= 10  |radius = 5

Midpoint ( %28x%5B1%5D+%2B+x%5B2%5D%29%2F2, %28y%5B1%5D+%2B+y%5B2%5D%29%2F2)

 Midpoint Pt(6,6), the center of the circle

Standard Form of an Equation of a Circle is %28x-h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2

where Pt(h,k) is the center and r is the radius

equation of a circle (x-6)^2 + (y-6)^2 = 25