Hi,         

 hyperbola with vertices (4,0) and (-4,0) 

Opens right and left along the x-axis with center at Pt(0,0)

Standard Form of an Equation of an Hyperbola opening right and left is:

   where Pt(h,k) is a center  with vertices 'a' units right and left of center.

  x^2/16 - y^2 /b^2 = 1

foci at (-c,0) and (c,0) where c^2 = a^2 + b^2

foci at (sqrt(20), 0) and (sqrt(20), 0)

 sqrt(20)^2 = 16 + b^2

  20 - 16 = b^2

     b^2 = 4

       b = ± 2

   x^2/16 - y^2 /4 = 1

 

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