# SOLUTION: find the vertex of the parabola,x2+4x+2y-7=0.

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 Question 391728: find the vertex of the parabola,x2+4x+2y-7=0.Answer by ewatrrr(10682)   (Show Source): You can put this solution on YOUR website! ``` Hi the vertex form of a parabola, where(h,k) is the vertex x2+4x+2y-7=0 OR y = (1/2)x^2 - 2x - 7/2 2y = -x^2 - 4x - 7 y = -(1/2)x^2 - 2x - 7/2 Completing the square to put into vertex form y = -(1/2)[x^2+4x] - 7/2 y = -(1/2)[(x+2)^2 - 4] -7/2 y = -(1/2)(x+2)^2 +2 -7/2 y = -(1/2)(x+2)^2 - 3/2 Vertex is Pt(-2,-3/2) This is a maximum point, parabola opens downward -(1/2) < 0 ```