SOLUTION: What would these equations be in standard form???
I know that this is a hyperbola - x^2-y^2-8x+10y+15=0
And this is a parabola - y^2+4y-8x+4=0
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-> SOLUTION: What would these equations be in standard form???
I know that this is a hyperbola - x^2-y^2-8x+10y+15=0
And this is a parabola - y^2+4y-8x+4=0
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Question 391114: What would these equations be in standard form???
I know that this is a hyperbola - x^2-y^2-8x+10y+15=0
And this is a parabola - y^2+4y-8x+4=0 Answer by solver91311(24713) (Show Source):
Divide the x-terms by the coefficient on . Since this is already 1, skip this step.
Divide the coefficent on the term by 2, square the result, then add that result to both sides of the equation. -8 divided by 2 is -4. -4 squared is 16. Add 16 to both sides.
Divide the y-terms by the coefficient on .
Divide the coefficent on the term by 2, square the result, then add that result to both sides of the equation. -10 divided by 2 is 5. 5 squared is 25. But consider the -1 coefficient in front of the parentheses. Add -25 to both sides.
Factor the two perfect square trinomials in the LHS and collect terms in the RHS.
Divide both sides by -24:
One problem per post, please.
John
My calculator said it, I believe it, that settles it
