SOLUTION: Find the length of the minor axis for the ellipse: (x+6)^2/1+ (y+9)^2/16=1.

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Question 390942: Find the length of the minor axis for the ellipse: (x+6)^2/1+ (y+9)^2/16=1.
Answer by Edwin McCravy(20059)   (Show Source): You can put this solution on YOUR website!
Find the length of the minor axis for the ellipse:

.

This is of the form



The larger denominator is under the term that contains y so the major 
axis is vertical and the minor axis is horizontal.

The center is (h,k) = (-6,-9)
a² = 16 so a = 4
b² = 1  so b = 1

a is one-half of the major axis and b is one-half or the minor axis.

To draw the graph, we start at the center, (-6,-9), draw half the
major axis upward from it and half of the major axis below it.
Also, starting at the center, (-6,-9), draw half the
minor axis leftward from it and half of the minor axis right of it.

   
 
Sketch in the ellipse:

 

Since one-half of the minor axis is b = 1, the entire minor axis is 2.

Edwin


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