Hi,        

factoring to find x when y = 0

 4x^2 + 4x - 8 = 0

 4[x^2 + x - 2} = 0

 4[(x-1)(x+2)]= 0 Note:SUM of the inner product(-x) and the outer product(2x) = x

 (x-1)(x+2)= 0

 (x-1)= 0

    x = 1  already determined:  Pt(1,0) named an x-intercept

 (x+2)= 0

    x = -2  Pt(-2,0) the other x-intercept



 

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