Hi,  

the vertex form of a parabola,  where(h,k) is the vertex

vertex (-2,-8)

y =a(x+2)^2 -8

using y-intercept pt(0,4) to find a

4 = a(-2)^2 -8

12 = 4a

 3 = a

y = 3(x+2)^2 -8  

finding x-intercepts when y = 0

0 = 3(x^2 + 4x + 4) -8 

0 =  3x^2 + 12x + 4





  Present these x values as is traditional for your classroom



 

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