Hi

y=-5x^2+15x-10

Factoring to find the x-intercepts when y = 0

 -5x^2 + 15x  - 10 = 0

 -5(x^2 - 3x + 2) = 0

 -5(x-2)(x-1)=0 Note:SUM of the inner product(-2x) and the outer product(-x) = -  (x-1)=0 

    x = 1  As the question states and...

  (x-2)=0

    x = 2

Please note vertex (3/2, 5/4 )

found by completing square for y = -5x^2+15x-10 = -5(x-3/2)^2 + 5/4)

the vertex form of a parabola,  where(h,k) is the vertex



 

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