Hi,         

Finding the x-intercepts defined by the equation: y =3x^2+3x-6

 3x^2 + 3x - 6 = 0   Note: y = 0 where the parabola crosses x-axis

 3(x^2 + x - 2)= 0

 Factoring

 (x+2)(x-1)=0 Note:SUM of the inner product(2x) and the outer product(-x) = 1*x

 (x+2)= 0

   x = -2

 (x-1)= 0 

   x = 1



 

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