# SOLUTION: one x-intercept for a parabola is at the point (0.6,0)use the quadratic formula to find the other x-intercept for the parabola defined by the equation: y=-5x^2+8x-3.

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 Click here to see ALL problems on Quadratic-relations-and-conic-sections Question 389241: one x-intercept for a parabola is at the point (0.6,0)use the quadratic formula to find the other x-intercept for the parabola defined by the equation: y=-5x^2+8x-3. Found 2 solutions by richard1234, ewatrrr:Answer by richard1234(5390)   (Show Source): You can put this solution on YOUR website!If we use the quadratic formula, = 0.6 or 1, so 1 is the other x-intercept. There's a simpler solution that doesn't involve the quadratic formula. If you know that the sum of the roots of the polynomial is -b/a = -8/-5 = 1.6, we have 1.6 = 0.6 + x, x = 1. Answer by ewatrrr(10682)   (Show Source): You can put this solution on YOUR website!``` Hi y= -5x^2+8x-3 at x-intercept , y = 0 -5x^2 + 8x - 3 = 0 uaing the Quadratic Formula to solve x = 6/10 = .6 (already determined by the question) x = 10/10 = 1 ```