SOLUTION: Find the center (h,k) 0f the circle with the equation x^2+y^2-6y=7 (h,k)=(__,__)

Algebra ->  Algebra  -> Quadratic-relations-and-conic-sections -> SOLUTION: Find the center (h,k) 0f the circle with the equation x^2+y^2-6y=7 (h,k)=(__,__)      Log On

Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!
Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!

   

Question 38903: Find the center (h,k) 0f the circle with the equation x^2+y^2-6y=7
(h,k)=(__,__)
Answer by mbarugel(146) About Me  (Show Source):
You can put this solution on YOUR website!
Hello!
We need to rewrite your equation to get the form:
%28x-h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2
Once we have the equation in this for, we know that the center is at (h, k)
You have:
x%5E2%2By%5E2-6y=7
%28x-0%29%5E2+%2B+y%5E2+-6y+-7+=+0
%28x-0%29%5E2+%2B+y%5E2+-6y+%2B+9+-+9+-7+=+0
%28x-0%29%5E2+%2B+y%5E2+-6y+%2B+9+-+16+=+0
%28x-0%29%5E2+%2B+%28y-3%29%5E2+-+16+=+0
%28x-0%29%5E2+%2B+%28y-3%29%5E2+=+16
%28x-0%29%5E2+%2B+%28y-3%29%5E2+=+4%5E2
So the center of this circle is at (h, k) = (0, 3)

I hope this helps!
Get more answers at Online Math Answers.com!