SOLUTION: Find the center (h,k) of the ellipse with the equation 9x^2-18x+4y^2+16y=11 Thanks:)

Algebra.Com
Question 38901: Find the center (h,k) of the ellipse with the equation
9x^2-18x+4y^2+16y=11
Thanks:)

Answer by fractalier(6550)   (Show Source): You can put this solution on YOUR website!
Okay from
9x^2 - 18x + 4y^2 + 16y = 11
9(x^2 - 2x + 1) + 4(y^2 + 4y + 4) = 11 + 9 + 16
9(x - 1)^2 + 4(y + 2)^2 = 36
(x - 1)^2 / 4 + (y + 2)^2 / 9 = 1
center is at (1, -2)

RELATED QUESTIONS

Find the center of an ellipse with the equation {{{9x^2 + 16y^2 - 18x + 64y =... (answered by mukhopadhyay)
Find the center of an ellipse with the equation {{{9x^2 + 16y^2 - 18x + 64y =... (answered by Edwin McCravy)
Find the center of an ellipse with the equation... (answered by Fombitz)
find the center of an ellipse with the equation 9x^2+16y^2-18x+64y=71 Find the foci... (answered by jsmallt9)
find the centre,foci,vertices,and graph the following conics 1)8y²+12x=0... (answered by MathLover1)
The Equation {{{9x^2-18x+4y^2+8y=23}}} defines an ellipse with center (____, ___). The... (answered by Earlsdon)
For the conic section described by the equation 9x^2+4y^2-18x+16y-11=0 What is the... (answered by lwsshak3)
Find the center, the vertices, and the foci of the ellipse... (answered by lwsshak3)
Find the center (h,k) and radius of the circle with given equation... (answered by ewatrrr)