SOLUTION: x=5y^2+40y+77 Find the vertex. So far I used (b/2)^2=(40/2)^2=20^2=400 Then x=(5y^2+40y+400)-400+77 Then x=5(y^2+8y+80)-323 I don't know what to do afterwards.

Question 388163: x=5y^2+40y+77
Find the vertex. So far I used (b/2)^2=(40/2)^2=20^2=400
Then x=(5y^2+40y+400)-400+77
Then x=5(y^2+8y+80)-323 I don't know what to do afterwards.
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Factor out the 5 first.

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