SOLUTION: Find the center, vertices, and foci for the ellipse: 4x^2+16y^2=64 Thanks:)

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Question 38780: Find the center, vertices, and foci for the ellipse: 4x^2+16y^2=64
Thanks:)

Answer by Nate(3500)   (Show Source): You can put this solution on YOUR website!



Center: (0,0)
Transverse axis: horizontal
a=4
b=2
c^2=a^2-b^2
c^2=16-4
c^2=12

Vertex: (4,0),(-4,0),(0,2),(0,-2)
Foci: (4 - ,0),(-4 + , 0)

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