SOLUTION: Explain how to find the distance from the focus to the directrix of the parabola x=2y^2. Note: y^2 is y squared

Hi

In general, for parabola opening up or down:

the vertex form of a parabola,  where(h,k) is the vertex

and 4p(y-k) = (x-h)^2 where (h,k) is the vertex and 

p the distance from the focus to the vertex. 



x = 2y^2  In this case(x takes the place of y) vertex is (0,0) and 'opens right' as a >0

 x/2 = y^2  therefore: 4p = 1/2  p = 1/8

Directrix(blue line) is the same distance from the parabola as the focus.

distance between the focus and the directrix is 1/8 + 1/8 = 1/4