SOLUTION: what would be the vertices, foci, and asymptotes of x^2/9-y^2/36=1
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Question 385710: what would be the vertices, foci, and asymptotes of x^2/9-y^2/36=1
Answer by robertb(5830) (Show Source): You can put this solution on YOUR website!
The equation represents a hyperbola. The center is at (0,0). Here ,, , or . Hence the foci are (, 0) and (, 0). Vertices are (-3,0) and (3,0). We can get the asymptotes by considering . This equation is equivalent to the equations y = -2x and y = 2x, and are the asymptotes of the hyperbola.
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