# SOLUTION: Convert 2x^2 + 2y^2 + 6x - 8y + 12 = 0 into center-radius form. I divided by 2 to get a coefficeint of one. then when I tried to complete the square I didn't know what to do wit

Algebra ->  Algebra  -> Quadratic-relations-and-conic-sections -> SOLUTION: Convert 2x^2 + 2y^2 + 6x - 8y + 12 = 0 into center-radius form. I divided by 2 to get a coefficeint of one. then when I tried to complete the square I didn't know what to do wit      Log On

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 Click here to see ALL problems on Quadratic-relations-and-conic-sections Question 385192: Convert 2x^2 + 2y^2 + 6x - 8y + 12 = 0 into center-radius form. I divided by 2 to get a coefficeint of one. then when I tried to complete the square I didn't know what to do with the 3. x^2 + 3x + ___ + y^2 + 4y + 2 = -6 + ____ + 2Answer by Fombitz(13828)   (Show Source): You can put this solution on YOUR website!Take (1/2) of 3 and square it, add it to both sides. Also, for you should add 4 and not 2 to both sides (again it's (1/2)4 squared).