# SOLUTION: name the vertex for the parabola with equation y=3x²-12x+16

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 Click here to see ALL problems on Quadratic-relations-and-conic-sections Question 38295: name the vertex for the parabola with equation y=3x²-12x+16Found 2 solutions by Nate, Paul:Answer by Nate(3500)   (Show Source): You can put this solution on YOUR website! original add constant divide by three complete the square combine add multiply by three Use stantard form where the vertex is (h,k). Vertex is (2,4). Answer by Paul(988)   (Show Source): You can put this solution on YOUR website!To find the vertex, comlpete the square. Using intercepts; y=0 Vertex: (2,4) Paul.