Hi,

Find the center and radius of the circle

The standard equation of a circle with center C(h,k) and radius r is :



x^2+y^2-6x+2y+6=0

(x-3)^2 + (y+1)^2 -9 -1 + 6 = 0

(x-3)^2 + (y+1)^2 = 4

(x-3)^2 + (y+1)^2 = 2^2

Center is Pt(3,-1) r = 2 

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