SOLUTION: what is the equation of the circle that has its center at (3,-1) and passes through the point (-2,2)

Question 374779: what is the equation of the circle that has its center at (3,-1) and passes through the point (-2,2)
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Start with the general equation of a circle.

Plug in and (since the center is the point (h,k) ).

Plug in and (this is the point that lies on the circle, which is in the form (x,y) ).

Combine like terms.

Square each term.

Add.

So because , , and , this means that the equation of the circle with center (3,-1) that goes through the point (-2,2) is

.

If you need more help, email me at jim_thompson5910@hotmail.com

Also, feel free to check out my tutoring website

Jim

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