# SOLUTION: Hi, I have to identify the conic of the equation below and find the center, vertices, and asymptotes: {{{x^2/9 + y^2/4 = 1}}} I can't find any examples like this so I'm lost

Algebra ->  Algebra  -> Quadratic-relations-and-conic-sections -> SOLUTION: Hi, I have to identify the conic of the equation below and find the center, vertices, and asymptotes: {{{x^2/9 + y^2/4 = 1}}} I can't find any examples like this so I'm lost       Log On

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 Click here to see ALL problems on Quadratic-relations-and-conic-sections Question 372311: Hi, I have to identify the conic of the equation below and find the center, vertices, and asymptotes: I can't find any examples like this so I'm lost here. Any help you can provide is greatly appreciated :)Found 2 solutions by robertb, solver91311:Answer by robertb(4012)   (Show Source): You can put this solution on YOUR website!It's an ellipse, with center at the origin (0,0), semi-major axis along the x-axis with length 3, and semi-minor axis 2. Vertices are (3,0) and (-3,0), and covertices (0,2) and (0,-2). There are no asymptotes of any kind (horizontal, vertical, slant, etc.) Answer by solver91311(16872)   (Show Source): You can put this solution on YOUR website! If you have a plus sign between the LHS terms, and... If , you have a circle center at , radius , but if you have an ellipse, center at , semi-major axis and semi-minor axis (unless and it is the other way around). If you have a minus sign, then you have a hyperbola, centered at If only one of the variables is squared, then you have a parabola. Only hyperbolas have asymptotes. For your example, , , and . So you have an ellipse, centered at the origin, semi-major axis of 3, and semi-minor axis of 2. The vertices are at and , the end points of the semi-minor axis are at and . Calculate . Then the foci are at and . Ellipses do not have asymptotes. John My calculator said it, I believe it, that settles it