SOLUTION: find the vertex the line of symmetry the maximum and minimum value of the quadratic function. F(x)=x^2-12x-3

SOLUTION: find the vertex the line of symmetry the maximum and minimum value of the quadratic function. F(x)=x^2-12x-3

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Question 370260: find the vertex the line of symmetry the maximum and minimum value of the quadratic function. F(x)=x^2-12x-3
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
The line of symmetry is x = -b/2a
x = 12/2
x = 6
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The minimum is F(6) = 36 - 72 - 3
= -39

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