SOLUTION: Determine what type of figure is given, then graph. Show all work and label all key points (asymptotes, foci, vertices, the directrix, the center) where applicable. X^2 + y^2 +

Question 36547: Determine what type of figure is given, then graph. Show all work and label all key points (asymptotes, foci, vertices, the directrix, the center) where applicable.
X^2 + y^2 + 4x � 6y = 3
Answer by venugopalramana(3286) (Show Source): You can put this solution on YOUR website!
TIP:
1.IF X^2 AND Y^2 HAVE EQUAL COEFFICIENTS AND THERE IS NO XY TERM ,IT
COULD BE A CIRCLE.
1.) X2 + y2 + 4x � 6y = 3
COMPLETE SQUARE.
(X^2+2*2X+2^2)-2^2+(Y^2+2*3Y+3^2)-3^2=3
(X+2)^2+(Y+3)^2=3+9+4=16=4^2
THIS IS THE EQN OF A CIRCLE WHOSE STD.FORM IS
(X-H)^2+(Y-K)^2=R^2,WHERE (H,K) IS THE CENTRE OF THE CIRCLE AND R IS
THE RADIUS.HENCE
(-2,-3) IS THE CENTRE AND 4 IS THE RADIUS.

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