SOLUTION: Express as a single logarithm and simplify:
logx+logy-logz-logw
how do I do this one?
Algebra.Com
Question 34188: Express as a single logarithm and simplify:
logx+logy-logz-logw
how do I do this one?
Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!
The log of a product is the sum of the logs.
The log of a quotient is the difference of the logs.
Thus
logx + logy - logz - logw =
logx + logy - (logz + logw) =
log(xy) - log(wz) =
log(xy/wz)
RELATED QUESTIONS
Can you pls help? How do I write this expression as a single logarithm?
1/2 logx +... (answered by stanbon)
how do you write 2[logx+logy] as a single... (answered by Alan3354)
I need to express log3x+6(logx-logy) as a single logarithm, and simplify if possible. I... (answered by jim_thompson5910)
How would I write the following expression as a single logarithm:... (answered by nabla)
How do I express this problem as a single... (answered by solver91311)
Express as a single logarithm and simplify: 1/3 logx y + 2/7 logx... (answered by Fombitz)
Express as a single logarithm and simplify: 1/3 logx y + 2/7 logx... (answered by nyc_function)
{{{logx^2+logy-3logx-logy^2}}}. as single... (answered by ankor@dixie-net.com)
how do you condense 1/3 (logx-2 logy+3... (answered by MathLover1)