SOLUTION: Find the equation of the parabola with vertex at (−2, 2) and directrix at y = 4

SOLUTION: Find the equation of the parabola with vertex at (−2, 2) and directrix at y = 4

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Question 334908: Find the equation of the parabola with vertex at (−2, 2) and directrix at y = 4
Answer by nyc_function(2741) (Show Source): You can put this solution on YOUR website!
Since the directrix is horizontal, then the general term of parabola is
(x-α)^2 = 4p(y-β) vertex (α,β) = (-2,2)
(x+2)^2 = 4p(y-2)
p is the distance from vertex to directrix = 2
The equation of parabola : (x+2)^2 = 8(y-2)

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