# SOLUTION: 6. What is the directrix of the parabola with the equation {{{y+3=(1/10) (x+2)^2}}} ?

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 Question 33190: 6. What is the directrix of the parabola with the equation ?Answer by venugopalramana(3286)   (Show Source): You can put this solution on YOUR website! STANDARD EQN.OF PARABOLA IS (X-H)^2=4A(Y-K)...WHERE FOCUS IS (H,K+A) DIRECTRIX IS Y-K+A=0 AXIS IS X-H=0 VERTEX IS (H,K) HERE WE HAVE (X+2)^2=10(Y+3)...SO COMPARING WE GET H=-2.....K=-3.....4A=10...OR...A=2.5...HENCE DIRECTRIX IS GIVEN BY Y-K+A=0....OR..... Y-(-3)+2.5=0 Y+3+2.5=0 Y+5.5=0 2Y+11=0