SOLUTION: Please help:
I have to find the center and the length of a radius of the circle:
X^2+Y^2-2x-8y+8=0
Thanks,
Algebra.Com
Question 32420: Please help:
I have to find the center and the length of a radius of the circle:
X^2+Y^2-2x-8y+8=0
Thanks,
Answer by mukhopadhyay(490) (Show Source): You can put this solution on YOUR website!
x^2+y^2-2x-8y+8=0
=>(x-1)^2 + (y-4)^2 = 3^2
Center is at (1,4) and radius is 3
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