SOLUTION: What is the range of y = 1 - x2; Domain = {-1, 0, 1} && y = 4x - x2; Domain = {-1, -2, 0} && y = t2 + t - 2; Domain = {-2, -1, 0, 1} && y = z2 - 3z; Domain = {-1, 0

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Question 316831: What is the range of y = 1 - x2; Domain = {-1, 0, 1}
&&
y = 4x - x2; Domain = {-1, -2, 0}
&&
y = t2 + t - 2; Domain = {-2, -1, 0, 1}
&&
y = z2 - 3z; Domain = {-1, 0, 1, 2}
&&& also how exactly do you find the domain like if the problem was y = 2/
x + 3
Thank you!
Katie'

Answer by Fombitz(32388)   (Show Source): You can put this solution on YOUR website!

Domain = {-1, 0, 1}



Range=(0,1)
.
.
.

Domain = {-1, -2, 0}



Range=(0,-5,-12)
.
.
.

Domain = {-2, -1, 0, 1}



Range=(0,-2)
.
.
.

Domain = {-1, 0, 1, 2}




Range=(4,0,-2)
.
.
.

The domain is all x for which the function makes sense.
For this function, all x are allowed except for the x which makes the denominator equal to zero because division by zero is undefined.
Find the value when the denominator equals zero.


So then the domain is, in interval notation,
(,)U(,)

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