SOLUTION: identify the conic section given by 121x^2=49+144y^2

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Question 310974: identify the conic section given by 121x^2=49+144y^2
Found 2 solutions by Fombitz, CharlesG2:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
121x%5E2-144y%5E2=49
%28121%2F49%29x%5E2-%28144%2F49%29y%5E2=1
Unequal coefficients for x%5E2 and y%5E2 with unequal signs points to a hyperbola.

Answer by CharlesG2(834) About Me  (Show Source):
You can put this solution on YOUR website!
identify the conic section given by 121x^2=49+144y^2
121x^2 = 49 + 144y^2
121x^2 - 144y^2 = 49
(121/49)x^2 - (144/49)y^2 = 1
this is a hyperbola