SOLUTION: find the area of the circle whose equation is: x^2-4x+y^2+12y-25=0 (hint: the equation for a circle is (x-h)^2+(y-k)^2=r^2 where (h,k) is the center and r is the radius)

Question 304041: find the area of the circle whose equation is: x^2-4x+y^2+12y-25=0
(hint: the equation for a circle is (x-h)^2+(y-k)^2=r^2 where (h,k) is the center and r is the radius)
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
find the area of the circle whose equation is: x^2-4x+y^2+12y-25=0
(hint: the equation for a circle is (x-h)^2+(y-k)^2=r^2 where (h,k) is the center and r is the radius)
.

Complete the square:

From here we see that:

square units

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