SOLUTION: What is the center and radius of (x-3)^2 + (y-6)^2 = 16?
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Question 301519: What is the center and radius of (x-3)^2 + (y-6)^2 = 16?
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
What is the center and radius of (x-3)^2 + (y-6)^2 = 16?
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r^2 = 16, so r = 4
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Standard form of a circle is
The center is at (h,k)
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