SOLUTION: What is the radius of the circle given by the equation below?
x2 - 14x + y2 - 10y = -38
Algebra.Com
Question 301031: What is the radius of the circle given by the equation below?
x2 - 14x + y2 - 10y = -38
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
x^2-14x+y^2-10y=-38 Completeing the squares we get:
(x^2-14x+49)+(y^2-10y+25)=-36+49+25
(x-7)^2+(y-5)^2=38
r^2=38
r=sqrt38
r=6.16 is the radius.
RELATED QUESTIONS
What is the radius of the circle given by the equation below?
x2 - 14x + y2 + 12y =... (answered by lwsshak3)
The equation for the circle is:
x2+y2+14x+10y−7=0 .
What is the center of... (answered by amfagge92)
What is the center of the circle given by the equation below?
x2 - 16x + y2 - 18y =... (answered by stanbon)
A circle is described by the equation x2 + y2 + 14x + 2y + 14 = 0. What are the... (answered by reviewermath)
What is the radius of the circle whose equation is x2 + y2 =... (answered by Alan3354)
A circle is defined by the equation x2 + y2 – x – 2y – = 0. What are the coordinates... (answered by Fombitz)
A circle is defined by the equation x2 + y2 – x – 2y – = 0. What are the coordinates for (answered by Alan3354)
A circle is defined by the equation x2 + y2 – x – 2y – = 0. What are the coordinates for (answered by ikleyn)