SOLUTION: What is the equation in standard form for the circle: x^2+y^2-4x+8y+4=0

Question 298099: What is the equation in standard form for the circle: x^2+y^2-4x+8y+4=0
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Rewrite in standard form:
Group the x-terms and the y-terms as shown:
Subtract 4 from both sides.
Now complete the square in x and y by adding the square of half the x-term coefficient and the square of half the y-term coefficient to both sides of the equation.
Simplify both sides of the equation.
Now factor the left side and simplify the right side.
Finally...
Compare with standard form...
and you can see that ,, and and this represents a circle with center at (-2, 4) and radius of 4.
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