SOLUTION: for the circle (x-2)^2+(y+3)^2=9 find the x and y intercepts. i need step by step

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Question 294735: for the circle (x-2)^2+(y+3)^2=9 find the x and y intercepts. i need step by step
Found 2 solutions by Fombitz, stanbon:
Answer by Fombitz(32388)   (Show Source): You can put this solution on YOUR website!
To find the x-intercepts, set y=0 and solve for x.






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To find the y-intercepts, set x=0 and solve for y.






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Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
for the circle (x-2)^2+(y+3)^2=9 find the x and y intercepts.
i need step by step
---------------------------
x-intercept = ?
Let y = 0 and solve for "x":
(x-2)^2 + 3^2 = 9
(x-2)^2 = 0
x = 2 with multiplicity two.
That means the circle touches the x-axis at x=2,
but does not pass through it.
------------------
y-intercept = ?
Let x = 0 and solve for "y":
(-2)^2 + (y+3)^2 = 9
(y+3)^2 = 5
y+3 = +-sqrt(5)
y = -3+sqrt(5); y = 3-sqrt(5)
===================================
Cheers,
Stan H.

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