SOLUTION: The graph of(x+1)^2/64-(y+2)^2/36=1

SOLUTION: The graph of(x+1)^2/64-(y+2)^2/36=1

Algebra.Com

Question 292928: The graph of(x+1)^2/64-(y+2)^2/36=1
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!

RELATED QUESTIONS
describe the graph of y^/25 - x^2/64... (answered by rchill)

trace the hyperbola y^2/36 - x^2/64 =... (answered by checkley71)

Find the foci of the ellipse with the equation:... (answered by lwsshak3)

Find the slopes of the hyperbola whose equation is... (answered by venugopalramana)

can you please help me graph... (answered by ichudov)

{{{x^2}}}+{{{y^2}}}=36 {{{(x^2)/(16)}}}+{{{(y^2)/(64)}}}=1 What are the points of... (answered by lwsshak3)

What is the graph of... (answered by Fombitz)

(x-2)^2/36+(y-1)^2/36=1 what does the graph look... (answered by Alan3354)

sketch the graph of:... (answered by Alan3354)