SOLUTION: given the equation of a circle x^2+y^2-10x+4y+13=0 find its center and its radius. im not sure i think its center is 10,-4 please help if possible

Question 282458: given the equation of a circle x^2+y^2-10x+4y+13=0 find its center and its radius. im not sure i think its center is 10,-4 please help if possible
Answer by dabanfield(803) (Show Source): You can put this solution on YOUR website!
given the equation of a circle x^2+y^2-10x+4y+13=0 find its center and its radius. im not sure i think its center is 10,-4 please help if possible
We need to get the equation in the standard form:
(x-h)^2 + (y-k)^2 = r^2.
In this form the center is at (h,k) with radius = r.
x^2 + y^2 - 10x + 4y + 13 = 0
(x^2 - 10x) + (y^2 + 4y) = -13
We can "complete the squares" by adding the same things to both sides:
(x^2 - 10x + 25) + (y^2 + 4y + 4) = -13 + 25 + 4
(x-5)^2 + (y+2)^2 = 16
The center is at (5,-2) and the radius is 4.
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