SOLUTION: Could you please show me how to do the following question because I got it wrong. The circle x^2 + y^2 - 2x - 3 =0 is stretched horizontally by a factor of 2 to obtain an ellispe.

Question 281498: Could you please show me how to do the following question because I got it wrong. The circle x^2 + y^2 - 2x - 3 =0 is stretched horizontally by a factor of 2 to obtain an ellispe. What is the equation of this ellipse in general form.Please help and thank you for your time.
Answer by CharlesG2(834) (Show Source): You can put this solution on YOUR website!
Could you please show me how to do the following question because I got it wrong. The circle x^2 + y^2 - 2x - 3 =0 is stretched horizontally by a factor of 2 to obtain an ellispe. What is the equation of this ellipse in general form.Please help and thank you for your time.
putting equation into standard form of
, where (h,k) is center of circle, and r is the radius
x^2 + y^2 - 2x - 3 = 0
x^2 - 2x + y^2 = 3
x^2 - 2x + 1 + y^2 = 4 (added 1 to both sides to complete the square)

or
center is (1,0) and radius is 2
another way to write this would be:

now to stretch this cicle horizontally by a factor of 2 and write the equation of the ellipse
, is the equation we want for the ellipse
stretch horizontally by factor of 2 --> a=2 becomes a=4 --> now a^2=16

and that is the equation of the ellipse

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