SOLUTION: I have to find the vertex, focus, which way it opens, the directrix, axis of symmetry, the length of LR, and the endpoints of LR. The equation is: (x+3)^2=10(y-4). So far I have tr

Question 281139: I have to find the vertex, focus, which way it opens, the directrix, axis of symmetry, the length of LR, and the endpoints of LR. The equation is: (x+3)^2=10(y-4). So far I have tried and found the vertex is: (-3,4) and the focus is: (-3,2.5), it opens up, the directrix is y=-2.5, and the axis of symmetry is x=-3. But when I tried to graph it it didn't work out. Can you help me?
Thank you.
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
the vertex is -3,4
it does open up
the focus is NOT -3,2.5 but -3, 6.5
the directrix is NOT y=-2.5 but y=3/2

RELATED QUESTIONS
I need to find the vertex, focus, directrix and axis of symmetry of the parabola:... (answered by lynnlo)

give the standard equation of (3x-2)^2=84y-12. Provide it's vertex, focus, directrix,... (answered by MathLover1)

Please help me solve this equation Find the Parabola properties and graph x^2+4x+2y=0 (answered by rothauserc)

Please help me solve this equation Find the Parabola properties and graph y^2+6x+6y=39 (answered by MathLover1,solver91311)

Find the features of the parabola which is x2+8x-18-6y=0. Find the vertex the focus the... (answered by Fombitz)

Find the focus, directrix, vertex and axis of symmetry x^2=1/8... (answered by MathLover1)

I have a few questions 1.) the vertex, focus, directrix,lr: of equation... (answered by richwmiller)

Determine the vertex,focus,endpoints of Latus rectum, directrix and axis of symmetry of... (answered by greenestamps)

x=(1/20)(y-1)^2+2 what is the vertex,focus,wat direction is opens,axis of symmetry and... (answered by stanbon)