SOLUTION: Find the slopes of the hyperbola whose equation is (y^2/64)-(x^2/36)=1.

SOLUTION: Find the slopes of the hyperbola whose equation is (y^2/64)-(x^2/36)=1.

Algebra.Com

Question 26656: Find the slopes of the hyperbola whose equation is (y^2/64)-(x^2/36)=1.
Answer by venugopalramana(3286) (Show Source): You can put this solution on YOUR website!
Find the slopes of the hyperbola whose equation is (y^2/64)-(x^2/36)=1.
DID YOU COPY THE PROBLEM PROPERLY?
SLOPES VARY WITH POINT..OR DO YOU MEAN ASYMPTOTES?
RELATED QUESTIONS
Find the slopes of the assymptotes of the hyperbola with equation x�/64 - y�/36=1 (answered by Nate)

find the center, vertices, foci, and slopes of the asymptotes for each hyperbola whose... (answered by ewatrrr)

trace the hyperbola y^2/36 - x^2/64 =... (answered by checkley71)

Find the center and radius of a circle whose equation is (x^2)-12x+84=(-y^2)+16y Find... (answered by lynnlo)

Find the slopes of the asymptotes of a hyperbola with the following equation.... (answered by galactus)

Find the slopes of the asymptotes of a hyperbola with the equation y� = 36 +... (answered by Edwin McCravy)

Find the slopes of the asymptotes of the hyperbola with the equation 36 = 9x^2 �... (answered by ewatrrr)

What is the vertices, foci, and slope of the asymptotes for the hyperbola whose equation (answered by Paul)

What is the vertices, foci, and slope of the asymptotes for the hyperbola whose equation... (answered by venugopalramana)