SOLUTION: Given the ellipse: 2x^2 + 6y^2 + 32x - 48y + 212 = 0 find.
a. The Center C
b. Length of Major Axis
c. Length of Minor Axis
d. Distance from C to foci
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Question 259707: Given the ellipse: 2x^2 + 6y^2 + 32x - 48y + 212 = 0 find.
a. The Center C
b. Length of Major Axis
c. Length of Minor Axis
d. Distance from C to foci
Answer by drk(1908) (Show Source): You can put this solution on YOUR website!
We have this original equation as
(i)
rearranging, we get
(ii)
complete the square to get
(iii)
to get
(iv)
dividing by 12, we get
(v)
---
center is (-8,4)
--
major axis = sqrt(6)
--
minor axis = sqrt(2)
--
distance to foci
sqrt(sqrt(6) - sqrt(2)) = sqrt(4) = 2
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