SOLUTION: Need to turn this into standard form... 4x^2+4y^2-24+16y-100=0 4x^2+4y^2+16y=124 4x^2+4y^2+16Y+(1/2 of 16 =8^2=64)=124 4x^2 +4y^2+16y+64-64=124-64 4x^2 + 4y^2+16y=64 4x^2+ (2

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Question 253258: Need to turn this into standard form...
4x^2+4y^2-24+16y-100=0
4x^2+4y^2+16y=124
4x^2+4y^2+16Y+(1/2 of 16 =8^2=64)=124
4x^2 +4y^2+16y+64-64=124-64
4x^2 + 4y^2+16y=64
4x^2+ (2y+4)^2=64 or 8^2
I know this is not right but i do not know what to do.

Found 2 solutions by jim_thompson5910, Edwin McCravy:
Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
Start with the given equation.


Combine like terms.


Add 124 to both sides.


Group the 'y' terms (ie any terms that have a 'y' in them)


From that group alone, factor out the GCF 4


Take half of the 'y' coefficient 4 and square it to get . Add AND subtract this value inside the parenthesis (so the equation isn't changed)


Add AND subtract the value 4 inside the parenthesis





Inside the parenthesis, group the first three terms.


Factor (which is a perfect square) to get


Distribute.


Add 16 to both sides.


Combine like terms.


Factor the GCF 4 from the left side.


Divide both sides by 4.


Reduce.


Take note that we can write as and as . Also, we can write as . So the last equation then becomes




which is in the form (which is a circle) where , , and . Recall that (h,k) is the center. So the center is (0,-2). Also, the radius is 'r' which means that the radius is units.


===========================================================

Answer:

So the standard form of the equation is which is a circle with radius of units and a center at (0,-2).


Note: your teacher will probably want a simplified answer. So s/he will probably want the answer of (since it's much cleaner looking). If you want to verify the answer, simply graph the two conic sections and you'll find that they are the same conic section.

Answer by Edwin McCravy(20056)   (Show Source): You can put this solution on YOUR website!




First of all notice that every term is divisible by 4,
so let's divide every term by 4:



Let's add 31 to both sides:



Let's complete the square of the last two terms 
on the left side.  We take the coefficient of y, which is 4, 
multiply it by , getting 2, then we square 2, and 
 is 4, so we add  to both sides:



Let's put parentheses around the last three terms on the left
side and combine the terms on the right:



Now factor the trinomials in the parentheses:



That can be written as



In fact you could have skipped the step before that.

The standard form for a circle is



Since you didn't have to complete the square on the
x term, because you only had an  term and
no x-term, then to get it in the standard form you
have to write  as  to have the
standard form, so the answer is





is the equation of a circle

which has center (h,k) and radius r



is the equation for a circle which has center

(0,-2) and radius  which is about 5.92

and has this graph:



----------------------------------------------

Are you sure there wasn't supposed to be an x after the -24?
The reason I ask that is I don't think when you are advanced 
enough to be studying circles, that your teacher would 
still be testing you on such an elementary thing as to see 
whether you could combine the terms -24 and -100.  So I'm going 
to assume you really meant:



First of all notice that every term is divisible by 4,
so let's divide every term by 4:



Let's group the the two terms in x first and the two terms
in y second, and add 25 to both sides:



To complete the square of the first two terms 
we take the coefficient of x, which is -6, multiply it by ,
getting -3, then we square -3, and  is 9, so we add 
to both sides:



Let's put parentheses around the first three terms and
combinethe terms on the right.



Now lwt's complete the square of the last two terms 
on the left side.  We take the coefficient of y, which is 4, 
multiply it by , getting 2, then we square 2, and 
 is 4, so we add  to both sides:



Let's put parentheses around the last three terms on the left
side and combine the terms on the right:



Now factor the trinomials in the two parentheses:



That can be written as



In fact you could have skipped the step before that.

That's the standard form for a circle 



which has center (h,k) and radius r



is the equation for a circle which has center

(3,-2) and radius  which is about 6.16

and has this graph:

 

Edwin




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